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  1. How do I calculate average atomic mass? - Socratic

    The more abundant an isotope is, the more it will contribute to the average atomic mass of the element. color (blue) ("avg. atomic mass" = sum_i "isotope"_i xx "abundance"_i) In the actual …

  2. What number of magnesium ATOMS are contained in a 12*g mass …

    What number of magnesium ATOMS are contained in a #12*g# mass of the metal?

  3. Question #021e1 - Socratic

    May 15, 2017 · In your case, you would have zinc-66, a nuclide of zinc that has a mass number equal to 66. Now, an atom's mass number, A, tells you the number of protons, which is given …

  4. An object has a mass of #4 kg#. The object's kinetic energy

    An object has a mass of #4 kg#. The object's kinetic energy uniformly changes from #150 KJ# to # 64KJ# over #t in [0,8s]#. What is the average speed of the object? Physics1D …

  5. Question #7c97b - Socratic

    The atomic mass number refers to the approximate total mass of one atom of the element. That is, the total mass of the protons, neutrons, and electrons in the element.

  6. Question #470a1 - Socratic

    Calculate the concentration of the diluted protein You took 15.0 µL of the sample and diluted it with 15.0 µL of buffer to get 30.0 µL of solution. You get the new concentration from a …

  7. Question #e7db4 - Socratic

    A_text (r) = 39 > The chemical equation for the reaction is "HCl + YOH →YCl + H"_2"O" Step 1. Calculate the moles of "HCl" n_text (HCl) = 0.0280 color (red) (cancel ...

  8. Question #a0387 - Socratic

    92.64 = m 1 + f n (* *) Notice that we have two equations with three unknowns, the mass of the sample, the number of moles it contains, and the fraction that dissociates. In order to be able …

  9. Site Map - Solution Formation Questions and Videos | Socratic

    How do you calculate the number of moles of potassium hydroxide that must be dissolved to make the following solution: 500 #cm^3# of 1 #mol##/##dm^3#? What is the maximum …

  10. Question #edb36 - Socratic

    The mass will be 492.8 g. Each 6.02xx10^23 molecules will equal one mole of a compound (regardless of whether it is methanol, or anything else). So, our first (of two) calculations must …